whole under root sec2A+cosec2A=tanA+cotA
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whole root √sec2A+cosec2A
=√1/sin2A×cos2A=1/sinA×cosA
replacing 1 by sin sqaure A+ cos square A
We get
tanA+cotA.
hence proved
if u like it mark as brainliest ans
=√1/sin2A×cos2A=1/sinA×cosA
replacing 1 by sin sqaure A+ cos square A
We get
tanA+cotA.
hence proved
if u like it mark as brainliest ans
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