Find the square root of the smallest square that is divisible by the number 6 11 and 12
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Answered by
1
Answer:
6= 2*3 12=2*2*3 11=11*1
lcm= 12*11
now the smallest sq must be div by 12*11
12*11=2^2*3*11
sq=2^2*3^2*11^2
root=2*3*11=66
Answered by
1
Hola mate
Here is your answer -
6= 2*3
12=2*2*3
11=11*1
lcm= 12*11
now the smallest sq must be div by 12*11
12*11=2^2*3*11
sq=2^2*3^2*11^2
root=2*3*11=66
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