Math, asked by vishwam82, 9 months ago

Find the square root of the smallest square that is divisible by the number 6 11 and 12

Answers

Answered by prishajain2004
1

Answer:

6= 2*3    12=2*2*3  11=11*1

lcm= 12*11

now the smallest sq must be div by 12*11

12*11=2^2*3*11

sq=2^2*3^2*11^2

root=2*3*11=66

Answered by temporarygirl
1

Hola mate

Here is  your answer -

6= 2*3  

12=2*2*3  

11=11*1

lcm= 12*11

now the smallest sq must be div by 12*11

12*11=2^2*3*11

sq=2^2*3^2*11^2

root=2*3*11=66

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