Question

Find the square root the complex number2+2√3 i​

Answer 1

therefore, x=

$\binom{ + } - \sqrt{3}$

y=

$\binom{ + }{ - } 1$

since the product is positive

x=$\sqrt{3}$
y=1

or

x$= - \sqrt{3}$and y
$= - 1$