Find the square roots of the complex number 3+4i
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2
Answer:
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Strategy: write down an equation satisfied by the square root, and solve it algebraically. Method: square root x+iy satisfies (x+iy)2 = 3 + 4i. Expand: x2-y2 +2xyi = 3+4i.
Step-by-step explanation:
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Answered by
6
Answer:
Let
3+4i
=
x
+i
y
Then (
3+4i
)
2
=(
x
+i
y
)
2
⇒3+4i=x−y+2i
xy
Comparing real part and imaginary part, we get
3=x−y and 2
xy
=4⇒xy=4
∴x+y=±5 ( As x
=−5;
x
is real part )
∴x=4,y=1⇒
x
=±2,y=±1
Hence square root is ±(2+i)
Step-by-step explanation:
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