Question

If tan (A+B) =√3, tan (A-B) = 0, find the value of Sin(A+B).

Answer 1

Answer:

GIVEN

tan(A+B)=√3, tan (A-B) = 0, find the value of Sin(A+B).

tan 60 =√3

∴A AND B ARE 30°

sin(A+B)

=sin(30°+30°)

=sin(60°)

=√3/2