Question

Find the square using (a + b) = a + B + ab identity a) 72​

Answer 1

Answer:  5184

Step-by-step explanation:

$(a+b)^{2} = a^{2} +b^{2} + 2ab$

⇒ $( 70 + 2)^{2}$ = $70^{2} +$ 2 ×70 × 2+$2^{2}$

                  = 4900 + 280 + 4

                  = 5184

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Answer 2

Answer:

5184

Step-by-step explanation:

72²=(70+2)²

(a+b)²=a²+2ab+b²

(70+2)²=70²+2(70*2)+2²

            =4900+280+4

            =5184

∴72²=5184

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