Question

find the squares of the following numbers using the identity (a+b)2 = a2 + 2ab + b2. a)610 b)102 c)305​

Answer 1

Answer:

1) 372100

2)10404

3)93025

Step-by-step explanation:

as you said

1) 610 can be written as (600+10)

=>610^2=600*600+10*10+2*600*10

=>610^2=360000+100+12000

=>610^2=372100

2)102 can be written as 100+2

=>102^2= 100*100+2*2+2*100*2

=>102^2=10000+4+400

=10404

3)305 can be written as 300+5

=> 90000+25+3000

=>93025

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Answer 2

Step-by-step explanation:

a.) first we will split the number 610 into 600 and 10

(600+10)2=(600)2+2*600*10+(10)2

(600+10)2=360000+12000+100

(600+10)2=372100

answer