Physics, asked by saneemali1, 10 months ago

Obtain the expression for the period of a magnet vibrating in a uniform magnetic field and performing S.H.M.

Answers

Answered by Fatimakincsem
51

The expression is given as T = 2 π √ l / m B

Explanation:

The time period of oscillation of a magnet in a uniform magnetic field 'B' is given by

Formula:

T = 2 π √ l / m B

Where

  • T = Time period
  • I =  Moment of inertia
  • M = mass of bob
  • B = magnetic filed

Time period of an oscillation body about a foxed point can be defined as the time taken by the body to complete one vibration around that particular point is called time period.

Answered by drishtipriya3574
13

Answer:

The expression is given as T = 2 π √ l / m B

Explanation:

The time period of oscillation of a magnet in a uniform magnetic field 'B' is given by

Formula:

T = 2 π √ l / m B

Where

T = Time period

I =  Moment of inertia

M = mass of bob

B = magnetic filed

Time period of an oscillation body about a foxed point can be defined as the time taken by the body to complete one vibration around that particular point is called time period.

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