Find the squares of the following using identities: (i) 310 (ii) 196
Answers
Answered by
0
Answer:
310^2
= (300 + 10)^2
= (300)^2 + (2×300×10) + (10)^2
= 90000 + 6000 + 100
= 96100
196^2
= (200 - 4)^2
= (200)^2 - (2×200×4) + (4)^2
= 40000 - 1600 + 16
= 38400 + 16
= 38416
i) (a+b)^2 = a^2 + 2ab + b^2
ii) (a-b)^2 = a^2 - 2ab + b^2
Answered by
2
Answer:
( i ) 196 .
= > square of an even no is even . It is a perfect square
Step-by-step explanation:
Similar questions