Find the standard deviation of first 10 even integer
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Answer:
Step-by-step explanation:
First 10 even integers are : 2 4 6 8 10 12 14 16 18 20
N = 10; total no.
Mean = (2+4+6+8+10+12+14+16+18+20)/10 = 11.1
X Y Mean(u) (Y-u) (Y-u)^2
1 2 11.1 -10.1 102.01
2 4 -9.1 82.81
3 6 -8.1 65.61
4 8 -7.1 50.41
5 10 -6.1 37.21
6 12 -5.1 26.01
7 14 -4.1 16.81
8 16 -3.1 9.61
9 19 -2.1 4.41
10 20 -1.1 1.21
By using the formula of standard deviation we get;
Standard Deviation = 6.293
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