if two digit number is four times the sum of its digits and twice the product of digits. find the numbers
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Here is your answer
Let the digit in the ones place be x and tens place be y
Hence the two digit number = 10y + x
Given that the two digit number = 4 times sum of its digits
⇒ 10y + x = 4(x + y)
⇒ 10y + x = 4x + 4y
⇒ 3x – 6y = 0
⇒ 3x = 6y
∴ x = 2y → (1)
It is also given that the two digit number = 2 times product of its digits
⇒ 10y + x = 2xy
Divide by xy both the sides, we get
10/x + 1/y =2
Putting x=2y from (1)
10/2y + 1/5 =2
5/y + 1/y = 2
6/y = 2
y=3
Hence x = 6
The two digit number is (10y + x) = 10(3) + 6 = 36
Hope it helps you!
Here is your answer
Let the digit in the ones place be x and tens place be y
Hence the two digit number = 10y + x
Given that the two digit number = 4 times sum of its digits
⇒ 10y + x = 4(x + y)
⇒ 10y + x = 4x + 4y
⇒ 3x – 6y = 0
⇒ 3x = 6y
∴ x = 2y → (1)
It is also given that the two digit number = 2 times product of its digits
⇒ 10y + x = 2xy
Divide by xy both the sides, we get
10/x + 1/y =2
Putting x=2y from (1)
10/2y + 1/5 =2
5/y + 1/y = 2
6/y = 2
y=3
Hence x = 6
The two digit number is (10y + x) = 10(3) + 6 = 36
Hope it helps you!
Answered by
1
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