Question

Find the strength of electrostatic field whose force on an electron is equal

to the weight of the electron. Given: - charge on each electron=1.6×10-

19C, mass of electron =9.1× 10−31kg, acceleration due to gravity g=

10m/s2

Guys it's a 12 standard question....on Electric fields and charge....plzz help me out​

Answer 1

Sorry i am in 11th

But i will try it after a year

$\huge \underline \bold \blue {♡here_is_your_answer♡:-}$

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Answer 2

Answer:

Hence, the strength of the electric field = 5.6 × 10^(-11) V/m

Explanation:

Force,F on electron with charge 'q' in electric field E is q× E

Weight of electron with mass m_E in gravity, g = m_E×g

For electric force to be equal to its weight F=m_E×g

This implies, q×E = m_E×g

Hence, E= m_E*g/q

m_E = 9.1x10^-31 Kg

g = 9.8 m/s^2

q = 1.6×10^-19 C

Putting in the numbers we get

E = 5.6x10^-11 V/m the required electric field.

Hence, the strength of the electric field = 5.6 × 10^(-11) V/m

NOTE : THE EXPLANATION OF THIS ANSWER IS GIVEN IN THE ATTACHMENT ALSO. KINDLY REFER TO THAT.

"A piece of 'Supplementary Counsel'" :-

• About Electric Field = An electric field surrounds an electric charge, and exerts force on other charges in the field, attracting or repelling them. Electric fields are created by electric charges, or by time-varying magnetic fields.

• About magnitude of electric field = The magnitude of the electric field is simply defined as the force per charge on the test charge. Since electric field is defined as a force per charge, its units would be force units divided by charge units. In this case, the standard metric units are Newton/Coulomb or N/C.