find the sum 1+3+6+..…... to 40 terms
Answers
Answered by
1
Answer:
a=1
d=3
an=40
sn=n/2[2a+(n-1) d]
s40=20[2+(39) 3]
s40= 2380
thnx mark brainlist
if this answer is wrong ur question is wrong because 3-1=2
and 6-3=3 common difference is not correct
Answered by
0
Step-by-step explanation:
sum to n terms= n/2(first term +last term)
sum to 40 terms= 40/2(1+40)
=>20×41
=>820
YOUR ANSWER IS 820
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