Question

Find the sum 12 +13+14: +...+352

a.14404
b.14400
c.1225
d. 15408
​

Answer 1

Answer:

c)1225 is the right answer by Navneet8654.......... pubg lover

Answer 2

Step-by-step explanation:

$\huge\bf{\mid{\overline{\underline{ANSWER:-}}\mid}}$

If you observe this sequence,they are in A. P

$\huge\bold{Given:-} \\ \\ a = t_1 = 12 \\ \\ t_2 = 13 \\ \\ d = 1 \\ \\ \huge\red{formula:-} \\ \\ S_n = \frac{n}{2} (a + l) \\ \\ t_n = a + (n-1) d \\ \\ \implies t_n = a + (n-1) d \\ \\ 352 = 12 + (n-1) 1 \\ \\ n = 352 - 11 = n \\ \\ \boxed{n = 341 } \\ \\ \implies S_n = \frac{n}{2} (a + l) \: \: where \: l = t_n \\ \\ S_{341} = \frac{341}{2} ( 12 + 352) \\ \\ S_{341} = 341 \times 182 \\ \\ \huge\boxed{S_{341} = 62062}$

#BAL

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