Question

find the sum 2+4+6......202​

Answer 1

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The given list is AP

d=4-2=2

d=2

a=2

An=a+(n-1)d

202=2(n-1)2

200/2=n-1

$\boxed{n=101}$

Sn=(n/2)(a+An)

Sn=101/2 (2+202)

Sn=101×204/2

Sn=101×102

Sn=10302

10302 is the answer

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