Question

find the sum 61+62+63+64............+100​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$sum \: of \: first \: 100 \: numbers \: is$

$</p><p>({n}^{2} + n)÷2 \\ = {100}^{2} + 100 \\ = (10000 + 100)÷2 \\ = 10100÷2 \\ = 5050$

$sum \: of \: first \: 60 \: numbers \: is$

$({60}^{2} + 60)÷2 \\ = (3600 + 60)÷2 \\ = 3660÷2 \\=1830$

$61 + 62 + 63 + ......................... + 100 \\ = (1 + 2 + 3 + 4 + ............... + 100) - (1 + 2 + 3 + 4 + ................ + 60) \\ = 5050 - 1830 \\ = 3220$

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