Question

The efficiency of heat engine is 30. If 60,0000 joules of heat is supplied to the engine then calculate the work done by the engine ?​

Answer 1

Answer:

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Explanation:

22.1 A heat engine absorbs 360 J of thermal energy and performs 25 J of work in each cycle.

Find (a) the efficiency of the engine

e = 25 J / 360 J

e = 0.069

e = 6.9%

and (b) the thermal energy expelled in each cycle.

1 - [Qc/Qh] = e = 0.069

Qc/Qh = 1 - 0.069

Qc/Qh = 0.931

Qc/Qh (0.931)

Qc = (360 J) (0.931)

Qc = 335 J

22.2 A heat engine performs 200 J of work in each cycle and has an efficiency of 30%. For each cycle, how much thermal energy is