find the sum all two digit number which are divisible by 2 and 3
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answer = 810
Step-by-step explanation:
a = 12
d = 6
an = 96
an = a + (n-1)d
96= 12+ (n-1) 6
96-12 =(n-1)6
84/6=n-1
14 +1 = n
15 = n
Sn =n/2 [a+an]
= 15/2 * 12+96
=15/2 *108
= 15*54
=810
sum of all no. divisible by 2 and 3 = 810
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