Math, asked by aneekethn, 10 months ago

Find the sum & the product of the zeroes of the polynomial 6x²-x-2.
Answer with steps

Answers

Answered by shrutirajak03
0

sum \: of \: zeroes \:  =  \frac{ - b}{a}  \\  =  >  \frac{1}{6}  \\ product \: of \: zeroes \:  =  \frac{c}{a}  \\  =  >  \frac{ - 2}{6}  =   >  \frac{ - 1}{3}

HOPE ITS HELPS U..

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Answered by gokul4909
2

Step-by-step explanation:

6x^2 - x - 2 = 0

6x^2 - 4x + 3x - 2 = 0

2x ( 3x - 2 ) + 1 ( 3x - 2 ) = 0

( 2x + 1 ) ( 3x - 2 ) = 0

X = - 1/2 , 2/3

Sum : - b/a = - (-1) / 6 = 1/6

Product : c/a = - 2/6 = - 1/3

Hope it helps you

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