Question

Find the sum and difference of two complex number a+ib and c+id geometrically.​ ​

Answer 1

Explanation:

is given that

z

1

=a+ib and

z

2

=c+id

Then

z

1

+z

2

=(a+c)+i(b+d)

Now

(z

1

+z

2

) is purely real.

Then the imaginary part has to be 0.

Hence

b+d=0.