Math, asked by bahubalishah46, 1 month ago

find the sum and product of roots of the quadratic equation on 3 X square + 7 x + 1 is equal to zero

Answers

Answered by ktworks007
1

Answer:

sum : a + b = -b/a

then, a = 3,  b = 7

  answer is -7/3.

Product :  a*b =  c/a

then, a = 3,  b = 7 , c = 1

answer is 1/3  

Step-by-step explanation:

Answered by Manmohan04
0

Given,

Quadratic equation \[ = 3{x^2} + 7x + 1\]

Solution,

Compare the given quadratic equation,\[3{x^2} + 7x + 1\] with standard equation,\[a{x^2} + bx + c\]

Values of coefficients,

\[\begin{array}{l}a = 3\\b = 7\\c = 1\end{array}\]

Sum of roots,

\[ =  - \frac{b}{a}\]

\[ =  - \frac{7}{3}\]

Product of roots,

\[ = \frac{c}{a}\]

\[ = \frac{1}{3}\]

Hence, the sum and product of roots are \[\left( { - \frac{7}{3}} \right)\] and \[\left( {\frac{1}{3}} \right)\].

Concept,

Consider a quadratic equation, \[a{x^2} + bx + c = 0\]

Sum of roots \[ =  - \frac{b}{a}\]

Product of roots \[ = \frac{c}{a}\]

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