Find the sum and product of roots of under root 3X ^2 _under root 6x_3 = 0
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✔️3x^2 -✔️6x-3=0 comparing it with ax^2 + bx +c =0 we get a= ✔️3 , b = -✔️6 and c= -3 now sum of roots = -b/a = ✔️6/✔️3 =✔️2 and product of roots = c/a = -3/✔️3 = -✔️3 answer
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so for the quadratic equation ax² + bx + c = 0
sum of roots , s = -b/a
product of the roots, p = c/a
so for the equation
we have a = √3 , b = - √6 , c = - 3
so s = √2
and p = -√3
sum of roots , s = -b/a
product of the roots, p = c/a
so for the equation
we have a = √3 , b = - √6 , c = - 3
so s = √2
and p = -√3
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