Math, asked by sofiya, 1 year ago

State the nature of roots of quadratic equation 9x^2=_1

sofiya: It refers to 9x square

sofiya: By the way I got the answer

sofiya: Thank you for seeing my question

Answers

Answered by thinkdifferent

9x^2 +1 =0 comparing it with ax^2 +bx +c = 0 we get a= 9 , b= 0 , c = 1 now D = ✔️b^2-4ac = ✔️0-4x9x1 = ✔️-36 => roots are imaginary

sofiya: Which type of roots is this?

thinkdifferent: When we get a minus sign in the root it shows that roots are imaginary

thinkdifferent: Mark as best Plz

Anonymous: anyway there is no use of taking root here. simply we can solve here by taking discriminent

thinkdifferent: Gud thank you

kvnmurty: 9 x^2 = -1 = i^2 ;; as i = root(-1). x = + 1/3 i or -1/3 i.. imaginary

Answered by poojan

9x^2 +1 =0 , here a=9, b=0, c=1
then, discriminent Δ = b² - 4ac
Δ = 0² - 4×9×1
Δ = -36
here the result obtained is less than 0. so, the roots are imaginary.

Anonymous: easily understandable. nice

kvnmurty: 9 x^2 = -1 = i^2 ;; as i = root(-1). x = + 1/3 i or -1/3 i.. imaginary number (0,1/3) or (0,-1/3)

sofiya: It was really helpful

sofiya: Thank you so much

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