Question

find the sum and product of the roots of √3x²+9x+6√3=0

Answer 1

for general equation $a x^{2} +bx+c$ = 0

formula for the sum of roots = -(b/a)
product of roots = c/a

here  a = $\sqrt{3}$ ,     b= 9,       c = $6 \sqrt{3}$

on putting the values in formula, we get

sum of roots = -($\frac{9}{ \sqrt{3} }$)
                     = - $3 \sqrt{3}$

product of roots = $\frac{6 \sqrt{3} }{ \sqrt{3} }$
                          = 6

Answer 2

sum of roots = -coeffecient of x/coefficient of x^2. = -9/√3 = -3√3

products of roots =constant/coefficient of x^2 = 6√3/√3 = 6