Question

Find the sum and product of the zeroes of quadratic polynomial x^2-3

Answer 1

Answer:

heya mate there's your answer

The general form of quadratic equation is x^2-(sum of roots )x +(product of roots)=0

given x^2-3=0

sum of roots is 0

product of roots is -3

hope it helps you

Thank you

Answer 2

The polynomial is as follows :-

P(x) = x² - 3

The direct method :-

x² - 3= (x+root3) (x-root3)

Hence,

$x = \pm \: \sqrt{3}$

Sum of zeroes will be

$= \sqrt{3} + ( - \sqrt{3} ) \\ \\ \\ = 0$

Product of zeroes :-

$= \sqrt{3} ( - \sqrt{3}) \\ \\ \\ = - 3$

By using Formula :-

Sum of zeroes = - b/a

Thus,

Sum will be

$= \frac{0}{1} \\ \\ \\ = 0$

Product of zero will be :-

$= \frac{c}{a} \\ \\ \\ = \frac{( - 3)}{1} \\ \\ \\ = ( - 3)$

Answer!