Question

find the sum and product of the zeros of the quadratic polynomial a)3x2+14x+8 b) x2-8 c)x2-(c-ab)x-abc. Plz help urgent

Answer 1

Answer:

Step-by-step explanation:

3x²+14x+8 = 0

3x²+12x+2x+8 = 0

3x(x+4)+2(x+4) = 0

3x+2 = 0, x+4=0

X= -2/3 , x = -4

Alpha = -2/3 , beta = -4

Alpha + beta = -2/3+(-4)

-2/3-4 = -2-12/4 = -14/3

Alpha. Beta = -2/3×-4 = 8/3

2. X²-8

(x+/8)(x-/8) = 0

X+/8 = 0 , x-/8 = 0

X= -/8 , x= /8

Alpha =-/8 , beta = /8

Alpha +beta = -/8+/8 = 0

Alpha. Beta = -/8×/8 = -8