Question

Find the sum and product of zeros of the polynomial 2 x cube minus 4 x square + 3 x minus 8

Answer 1

HEY mate here is your answer:-

2x³ - 4x² + 3x - 8

sum of zeroes =

$\alpha + \beta + \gamma = - b \div a$

$\alpha \beta \gamma = - d \div a$

so, sum = -b/a = 4/2= 2

product = -d/a = 8/2= 4

hope it helps you ...

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Answer 2

The sum of the polynomial = 2 and the product of the polynomial = 4.

Step-by-step explanation:

The given polynoial:

$2x^{3} -4x^{2} +3x-8$

Here, a = 2, b = - 4, c = 3 and d = - 8

To find, the sum and product of zeros of the given polynomial = ?

Let α, β and $\gamma$ be the roots of polynomial.

∴ The sum of the polynomial, α + β + $\gamma$ = $\frac{-b}{a}$

$=\frac{-(-4)}{2}=2$

The product of the polynomial, α β$\gamma$= $\frac{-d}{a}$

$=\frac{-(-8)}{2}=4$

Hence, the sum of the polynomial = 2 and the product of the polynomial = 4.