Question

find the sum and the product of the zeroes of the polynomial X2-6×+5.​

Answer 1

Given :–

• A polynomial, x² – 6x + 5.

To Find :–

• Sum of the zeroes of the polynomial.
• Product of the zeros of the polynomial.

Solution :–

We know that,

$\boxed{ \red{ \alpha + \beta = \dfrac{ - b}{a}} }$

And,

$\boxed{\red{ \alpha \times \beta \: (\alpha \beta )= \dfrac{c}{a} }}$

So,

According to the question,

• Value of a = 1.
• Value of b = –6.
• Value of c = 5.

Now, we have to find the sum and product of the zeroes of the given polynomial.

• Sum of the zeroes of the polynomial is,

⟹ $\dfrac{-(-6)}{1}$

Now, open the bracket.

⟹ $\dfrac{6}{1}$

⟹ 6

• Product of the zeroes of the polynomial is,

⟹ $\dfrac{5}{1}$

⟹ 5

Hence,

1. Sum of the zeroes of the given polynomial = 6.
2. Product of the zeroes of the given polynomial = 5.

Answer 2

Answer:

given polynomial is ?/???>??

Step-by-step explanation:

DON'T KNOW ‍♀️‍♀️