Question

find the sum first 50 whole number
​

Answer 1

$\huge\star{\underline{\underline{\tt{\red{\mid{Answer \implies 1275}}}}}}\star$

$\large{\boxed{\green{\tt{\underline{Explanation}}}}}$

____________________________________

$\bold{\underline{\purple{\boxed{Sum\:of\:Terms \implies}}}}$$sn = \frac{n}{2} (a + l)$

First Term = a = 1

Last Term = l = 50

Number of Terms = n =50

So,

By substituting these values in the formula given above we get

$\implies$ $\frac{50}{2}$ (1+50)

$\implies$ 25 x 51

$\huge\implies$ 1275

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Answer 2

$\huge{\mathfrak{\underline{\underline{\red{Answer :-}}}}}$

1225

$\large{\green{\mathrm{To \: Find :-}}}$

Sum of first 50 whole number

$\large{\green{\mathrm{Given:-}}}$

A.P :- 0, 1, 2, 3,......... 49.

First term(a) = 0

Common Difference(d) = 1

Last term(L) = 49

Number of terms(n) = 50

$\large{\green{\mathrm{Solution:-}}}$

Using Formula

$\large{\boxed{\boxed{\red{S_{n} = \frac{n}{2}[2a + (n - 1)d]}}}}$

_______________[Put Values]

$\sf{S_{n} = \frac{50}{2}[2 * 0 + (50 - 1){\times}1}]$

$\sf{S_{50} = 25(0 + 49)}$

$\sf{S_{50} = 25(49)}$

$\bf{S_{50} = 1225}$

$\large{\boxed{\boxed{\red{S_{50}= 1225}}}}$