Question

Find the sum of 0.6.1.7.2.8.... to 100 terms​

Answer 1

Given AP:  0.6, 1.7, 2.8, ............ 

a = 0.6

d = 1.7 - 0.6 = 1.1

n = 100

Sn = n/2[ 2a + (n-1)d]

     = 100/2 [ 2(0.6) + (100 - 1)×(1.1)]

     = 50[ 1.2 + (99 × 1.1)]

     = 50[ 1.2 + 108.9]

     =50[110.1]

     = 5505

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Answer 2

Step-by-step explanation:

a=0.6 n=100 d=(1.7-0.6)= 1.1

Sn= n/2(2a+(n-1)d)

= 100/2(2(0.6)+(100-1)1.1)

= 50(1.2 +(99)1.1)

=50(1.2+108.9)

=50(110.1)

=5505