find the sum of 0.6,1.7,2.8,..............to100terms
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Answered by
71
Here, a = 0.6, d = 1.1 and n = 100.............
Sum of n terms can be given as follows: sum of n terms..................
10 arithmetic progression exercise solution..........
Thus, sum of the 100 term of given AP (Sn)= 5505..
Sum of n terms can be given as follows: sum of n terms..................
10 arithmetic progression exercise solution..........
Thus, sum of the 100 term of given AP (Sn)= 5505..
khushbu2:
thanku..when i tried even i got the same but was confused..thanks a lot..
Answered by
222
Given AP: 0.6, 1.7, 2.8, ............
a = 0.6
d = 1.7 - 0.6 = 1.1
n = 100
Sn = n/2[ 2a + (n-1)d]
= 100/2 [ 2(0.6) + (100 - 1)×(1.1)]
= 50[ 1.2 + (99 × 1.1)]
= 50[ 1.2 + 108.9]
=50[110.1]
= 5505
a = 0.6
d = 1.7 - 0.6 = 1.1
n = 100
Sn = n/2[ 2a + (n-1)d]
= 100/2 [ 2(0.6) + (100 - 1)×(1.1)]
= 50[ 1.2 + (99 × 1.1)]
= 50[ 1.2 + 108.9]
=50[110.1]
= 5505
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