Find the sum of 1.1+2.3+3.5+4.7+.........up to n terms
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Sn=n/2 [2a+(n-1)d]
=n/2 [2×1.1+(n-1)×1.2]
=n/2(2.2+1.2n-1.2)
=n/2 (1+1.2n)....
hope it helps.
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