Math, asked by lucky1854, 1 year ago

find the sum of (1-(1/n+1))+(1-(2/n+1))+(1-(3/n+1))+.........+(1+(n/n+1))​

Answers

Answered by jessica99
0

the formula is n (n+1)/2

Now we substitute

1(1/n+1)/2=1/n+1=0

1/n=-1

n=-1

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