find the sum of 1+4+7+10.....to 22 terms
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Hey dear friend
Given A.P.=1,4,7,10
where a=1 d=>4-1=3. n=22
By the formula
Sn= n/2[2a+(n-1)d]
Sn=22/2[2*1+(22-1)3]
Sn=11[2+21*3]
Sn=11[2+63]
Sn=11*65
Sn=715
So, the sum up to 22 terms is 715.
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Given A.P.=1,4,7,10
where a=1 d=>4-1=3. n=22
By the formula
Sn= n/2[2a+(n-1)d]
Sn=22/2[2*1+(22-1)3]
Sn=11[2+21*3]
Sn=11[2+63]
Sn=11*65
Sn=715
So, the sum up to 22 terms is 715.
perfectly fine pure correct answer
hope it helps you mark me as brainliest and follow me
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