find the sum of 1 st 100 even natural number which are divisibility by 5
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Step-by-step explanation:
The first few even natural number which are divisible by 5:- 10,20,30,40...
This is an AP in which a=10, d=(20-10)=10, and n=100
the sum of the n terms of an AP is given by:
Sn= n/2 [2a (a + (n - 1) d]
=> (100/2) × [2×10( 10+ (100-1) 10]
=> 50×[ 20 + 990 ]
=> 50× 1010
=> 50500
Hence, the number of first hundred even natural numbers which is divided by 5 is 50500.
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