find the sum of 1 to 200 without actual calculation find its pattern and explain it
Answers
Answered by
5
Answer:
If a sequence be 1+2+3+....+n then value is
n(n+1) / 2
so 1+2+3+...+200= 200*201/2= 20100
Answered by
2
Step-by-step explanation:
We have A.P = 1,2,3,45........200.
First term (a) = 1
last term (l) = 200
common difference(d) = 1
No. of terms (n) = 200
We know that Sn = n/2( a+l) [ See By Ju's ]
So, Sn = 200/2( 200+1)
=>100(201)
= 20100 Ans..
Hope It Helps..... :)
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