find the sum of 10 term of AP 50,46 ,42.
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Answer:
a = 50
d = -4
n = 10
an = a+ (n-1) d
a10 = a+ 9d
a10 = 50 + 9 (-4)
a10 = 50 + (-36)
a10 = 50- 36
a10 = 14
a10 = l
S = n÷2 { a + l}
S = 10 ÷ 2 { 50 + 14 }
S = 5 { 64 }
S = 320
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