Find the sum of 10 terms of an AP 50,46,42...
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Answer:
answer of this Q. is 320
Step-by-step explanation:
Sn=n/2{2a+(n-1)d}
S10=10/2{2×50+(10-1)×-4}
=5(100+9×-4)
=5(100-36)
=5×64
=320
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