Question

Find the sum of 10 terms of gp, first term and common ratio are 8 and 3

Answer 1

a+(n-1)d
=8+9*3=36
answer

Answer 2

The sum of 10 terms in a geometric progression is 236192.

Given:

The first term(a) and common ratio(r) are 8 and 3 in a geometric progression.

To Find:

The sum of 10 terms in a geometric progression.

Solution:

We are required to find the sum of 10 terms in a geometric progression.

The first term(a) = 8

Common difference, r = 3       [∵ r > 1]

n = 10 terms

The sum of n terms in a geometric progression is given as

Sₙ = a[(rⁿ – 1)/(r – 1)] if r ≠ 1and r > 1    -------(1)

Substitute the value of a, r, and n in equation(1) we get

Sₙ = 8×[(3¹⁰-1)/(3-1)]

Sₙ = 8×[(59049-1)/(2)]

Sₙ = 8×[59048/2]

Sₙ = 8×29524

Sₙ = 236192

Therefore, The sum of 10 terms in a geometric progression is 236192.

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