find the sum of 100 odd numbers istarting with 1
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a = 1
d = 2
n = 100
Sn = n/2 [ 2a + (n-1)d]
= 100/2 [ 2(1) + (100-1)(2)]
= 50 ( 2 + 198)
= 50 × 200
= 10000
Required sum = 10000
d = 2
n = 100
Sn = n/2 [ 2a + (n-1)d]
= 100/2 [ 2(1) + (100-1)(2)]
= 50 ( 2 + 198)
= 50 × 200
= 10000
Required sum = 10000
kaifarshad:
what is a d n
a is first term of arithmetic progression
D is common difference
n is number of terms
I am read in class 7
oh... its in class 10th
can you type the question again here
find the sum of 100 odd numbers starting with 1
i don't think there is any other method, may be there is any other, but sorry i don't know
frauod
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