find the sum of 10th term of an a p 2 5 8 11
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Step-by-step explanation:
2 5 8 11
t1=2 t2=5 t3=8 t4=11
by the formula
S=n/2[2a+(n-1)d]
a=2
n=10
d=t2-t1
=5-2
=3
S=10/2[4+(9)3]
=5[4+27]
=5×33
=165
the sum of 10th term of an a p 2 5 8 11 is 165
hence proved
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