find the sum of 15 terms of an AP -3,-5,-7-9
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Solution:-
Given sequences is
=> - 3 , - 5 , -7 , - 9
=> Common difference ( d ) = a₂ - a₁ = -5 - ( - 3 ) = - 2
=> First term ( a ) = -3
Formula
=> Sₙ = n/2 { 2a + ( n - 1 )d }
To find :- S₁₅
=> S₁₅ = 15/2 { 2 × -3 + ( 15 -1 ) × - 2 }
=> 2S₁₅ = 15{ - 6 + 14 × - 2 }
=> 2S₁₅ = 15 { - 6 - 28 }
=> 2S₁₅ = 15 × - 34
=> 2S₁₅ = - 510
=> S₁₅ = -510/2
=> S₁₅ = -255
Answer
=> Sum of 15terms is -255
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