find the sum of 15 terms of an ap whose first and last term 5 and 75
Answers
Answered by
8
a = 5
n = 15
L = 75
Sn = n/2 ( a + L)
Sn = 15 /2 ( 5 + 75)
= 15 × 80 /2
= 15 × 40
= 600
Required sum = 600
n = 15
L = 75
Sn = n/2 ( a + L)
Sn = 15 /2 ( 5 + 75)
= 15 × 80 /2
= 15 × 40
= 600
Required sum = 600
Answered by
7
Heya !!
First term ( a ) = 5
Last term ( d ) = 75
sn = n/2 × ( a + l )
s 15 = 15/2 × ( 5 + 75 )
=> 15/2 × 80
=> 15 × 40
= 600
First term ( a ) = 5
Last term ( d ) = 75
sn = n/2 × ( a + l )
s 15 = 15/2 × ( 5 + 75 )
=> 15/2 × 80
=> 15 × 40
= 600
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