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Let us consider,
ax+by=a+b---(1)
ax+b(x+y)=a+b----(2)
Equate(1) & (2)..,,
ax+by=ax+b(x+y)
by=b(x+y)
y=b(x+y) / b
y=x+y
x=y-y
x=0
substitute x=0 in (1)..,
ax+by=a+b
a(0)+by=a+b
by=a+b
y=a+b/b
ax+by=a+b---(1)
ax+b(x+y)=a+b----(2)
Equate(1) & (2)..,,
ax+by=ax+b(x+y)
by=b(x+y)
y=b(x+y) / b
y=x+y
x=y-y
x=0
substitute x=0 in (1)..,
ax+by=a+b
a(0)+by=a+b
by=a+b
y=a+b/b
kjha76776:
thanks but what is value of y
Answered by
1
ax+by=a+b....(i)
ax+b(x+y)=a+b.....(ii)
In (i),
ax+b(x+y)=a+b.....(ii)
In (i),
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