Find the sum of 17 term of an ap whose 4 term and 9 term are –15 and –30
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Answer:
4th term=a+3d=(-15)
a=(-15)-3d
9th term=a+8d=(-30)
-15-3d+8d=(-30)
5d=(-15)
d=(-3)
a=(-15)-3(-3)=(-5)
Sum=17/2{2×(-5)+(17-1)+(-3)}
=17(-5-24)
=17(-29)=(-493)
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