find the sum of 18+15 1/2+13+...+(-49 1/2)
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We have , a = 18
d = 1512 − 18 = 312 − 18 = −52
Let an = −4912 = −992
now, an = a + (n−1) d ⇒−992 = 18 + (n − 1)(−52) ⇒ − 992 = 18 − 5n2 + 52 ⇒ −992= 36 + 5 − 5n2 ⇒−99 = 41 − 5n ⇒ 5n = 41 + 99 ⇒5n = 140 ⇒n = 28
so the no. of terms = 28/////this is your answer i think it may help you
d = 1512 − 18 = 312 − 18 = −52
Let an = −4912 = −992
now, an = a + (n−1) d ⇒−992 = 18 + (n − 1)(−52) ⇒ − 992 = 18 − 5n2 + 52 ⇒ −992= 36 + 5 − 5n2 ⇒−99 = 41 − 5n ⇒ 5n = 41 + 99 ⇒5n = 140 ⇒n = 28
so the no. of terms = 28/////this is your answer i think it may help you
onlyannu:
no its not a right answer
Answered by
1
Answer:103
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