Question

find the sum of 1st 100 even natural numbers.​

Answer 1

The sum of the first 100 even natural numbers is 10100

Step-by-step explanation:

We have to find the sum of the first 100 even numbers.

So,

The formula is used to determine such a given series.

$\bold{Formula:- \dfrac{n(n+2)}{4} }$

where,

n - represents the last number in the series which is 200.

In other series, the 2 would be equal to the amount between each pair of numbers, and the 4 would be twice the amount.

To solve, substitute the values in the given formula:

$= \dfrac{200(200+2)}{4}$

$= \dfrac{200(202)}{4}$

$= \dfrac{40400}{4}$

= 10100

Therefore, the sum of the first 100 even numbers is 10100.

Answer 2

Answer:

The sum of the first 100 even natural numbers is 10100

Step-by-step explanation:

We have to find the sum of the first 100 even numbers.

So,

The formula is used to determine such a given series.

Formula:- n(n+2)/4

where,

n - represents the last number in the series which is 200.

In other series, the 2 would be equal to the amount between each pair of numbers, and the 4 would be twice the amount.

To solve, substitute the values in the given formula:

n(n+2)/4

={200(200+2)/4

{200(202)/4

40400/4

= 10100

Therefore, the sum of the first 100 even numbers is 10100.