Question

find the sum of 25 term of an a.p 3,8,13​

Answer 1

Answer:

n= 25

a= 3

d=5

Sn = n[2a +(n-1)d]/2

Sn = 25[2(3) + (25-1)5]/2

Sn= 25[6+24(5)]/2

Sn= 25[6+120]/2

Sn= 25[126]/2

Sn = 25×63

Sn = 1575

hope it helps ❤

Answer 2

Answer:

Step-by-step explanation:

a=3 d =5

n = 25

Sn =n/2+2a +(n-1)d

25/2+2 (3)+(25-1)5

25/2+6+24 (5)

25/2+6+120

25/2+126

25×63=1575

Hope this answer will help you

Hope this answer will help you