.find the sum of 25 term of an A.P having common
difference 6 and 18 term is 110
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Answer:
d=6
a18=110
a+17d=110
a + 17 *6= 110
so, a= 110- 102
a=8
now, s25= 25/2 { 2 *8 + ( 25-1}6 }
25\2 [ 16 +144]
25/2* 180
25 * 90
therfore, s25= 2250
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