Find the sum of 25 terms of an AP in which the third term is 7 and 7 term is two more than thin
of its third term
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a+2d=7
a+6d=2+3(a+2d)
=2+3a+6d
from above
a=-1,Putting in first eqation
d=4
hence sum of 25 terms =25/2(-2+(24)d)
=25/2(94)
=25×47
=1175
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